How to Find All Links On a Website?

Best practices

Ensure the `requests` library is up-to-date to avoid any compatibility issues with websites and to use the latest features and security fixes.
Use `soup.find_all('a', href=True)` to directly filter out `a` tags without an `href` attribute, making the code more efficient.
Validate and clean the URLs extracted to handle relative paths and possible malformed URLs properly.
Consider using `requests.Session()` for making multiple requests to the same host, as it can reuse underlying TCP connections, which is more efficient.

# Import libraries
import requests
from bs4 import BeautifulSoup

# Define the target URL
url = 'https://sandbox.oxylabs.io/products'

# Send HTTP request
response = requests.get(url)

# Parse HTML content
soup = BeautifulSoup(response.text, 'html.parser')

# Extract all anchor tags
anchors = soup.find_all('a')

# Print all href attributes from anchor tags
for link in anchors:
if link.get('href'):
print(link.get('href'))

# Alternative method using list comprehension
links = [link.get('href') for link in soup.find_all('a') if link.get('href')]
print(links)

Common issues

Ensure your script handles exceptions like `requests.exceptions.RequestException` to manage potential connectivity issues or HTTP errors gracefully.
Set a user-agent in your requests header to mimic a browser visit, which can help avoid being blocked by some websites that restrict script access.
Utilize `response.raise_for_status()` after your `requests.get()` call to immediately catch HTTP errors and handle them before parsing the HTML.
Incorporate a timeout in your `requests.get()` call to avoid hanging indefinitely if the server does not respond.

# Bad: Not handling exceptions which might occur during the request
response = requests.get(url)

# Good: Handling exceptions to avoid crashes due to connectivity issues
try:
response = requests.get(url)
except requests.exceptions.RequestException as e:
print(f"Error: {e}")

# Bad: Not setting a user-agent, might get blocked by websites
response = requests.get(url)

# Good: Setting a user-agent to mimic a browser
headers = {'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/58.0.3029.110 Safari/537.3'}
response = requests.get(url, headers=headers)

# Bad: Not checking for HTTP errors which can lead to parsing invalid content
response = requests.get(url)

# Good: Using raise_for_status to catch HTTP errors
response = requests.get(url)
response.raise_for_status()

# Bad: No timeout, request might hang indefinitely
response = requests.get(url)

# Good: Setting a timeout to avoid hanging indefinitely
response = requests.get(url, timeout=10)